A cura di: Francesco Speciale
Calcolare il valore della seguente espressione:
$((cos^2(18^circ))-(sin^2(18^circ)))/((cos^2(240^circ)))-(tg^2(-18^circ))$
$(cos^2(18^circ)-sin^2(18^circ))/(cos^2(240^circ))-tg^2(-18^circ)=
Essendo $cos(18^circ)=1/4sqrt(10+2sqrt5) , sin(18^circ)=1/4(sqrt5-1) , cos(240^circ)=-1/2 , tg(-18^circ)=-sqrt(1-2/5sqrt5)$,
sostituendo nell’espressione si ha:
$=((1/4sqrt(10+2sqrt5))^2-(1/4(sqrt5-1))^2)/((-1/2)^2)-(-sqrt(1-2/5sqrt5))^2=$
$=(1/(16)(10+2sqrt5)-1/(16)(sqrt5-1)^2)/(1/4)-(1-2/5sqrt5)=$
$=(1/(16)(10+2sqrt5)-1/(16)(5+1-2sqrt5))/(1/4)-(1-2/5sqrt5)=$
$=(5/8+(sqrt5)/8-3/8+(sqrt5)/8)*4-1+2/5sqrt5=(1/4+(sqrt5)/4)*4-1+2/5sqrt5=$
$=1+sqrt5-1+2/5sqrt5=(5sqrt5+2sqrt5)/5=7/5sqrt5$.
- Trigonometria