A cura di: Administrator

$f(x) = frac{1 – x^2}{4 – x^2}$
$f'(x) = frac{-2x (4 – x^2) – (1 – x^2) cdot (-2x)}{(4 – x^2)^2} =$ $frac{-2x (4 – x^2 – 1 + x^2)}{(4 – x^2)^2} =$ $frac{-6x}{(4 – x^2)^2}$