$f(x) = \frac{x \log x}{1 + \log x}$

A cura di: Administrator

$f(x) = frac{x log x}{1 + log x}$ $f'(x) = frac{(1cdot log x + xcdot 1/x)cdot (1 + log x) – (x log x) cdot 1/x}{(1 + log x)^2} =$ $frac{(log x + 1)^2 – log x}{(1 + log x)^2} =$ $1 – frac{log x}{(1 + log x)^2}$