A cura di: Administrator

$f(x) = frac{x^2 – 1}{1 – 2x}$
$f'(x) = frac{2x (1 – 2x) – (x^2 -1) (-2)}{(1 – 2x)^2} =$ $frac{2x – 4x^2 + 2x^2 -2}{(1 – 2x)^2} =$ $frac{-2 (x^2 -x +1)}{(1 – 2x)^2}$