A cura di: Administrator

Limite in forma indeterminata $frac{infty}{infty}$

$lim_{x rightarrow -infty} frac{2x-sqrt{4x^2-x+3}}{x-sqrt{6-x}} =$

$ lim_{x rightarrow -infty} frac{2x +xsqrt{4-frac{1}{x}-frac{3}{x^2}}}{x+xsqrt{frac{6}{x^2}-frac{1}{x}}} =$

$lim_{x rightarrow -infty} frac{2+sqrt{4-frac{1}{x}-frac{3}{x^2}}}{1+sqrt{frac{6}{x^2}-frac{1}{x}}} = 4$