A cura di: Administrator

Il limite si presenta in forma indeterminata $0cdot infty$.

Si ha

$lim_{xrightarrow 0^+}sin x ln x =$$lim_{xrightarrow 0^+}frac{sin x}{x}cdot lim_{xrightarrow 0^+} xln x$$text{posto } frac{1}{x} = t$$1cdot lim_{trightarrow +infty} frac{ln 1/t}{t} = lim_{trightarrow +infty} frac{-ln t}{t} = 0$