A cura di: Administrator

Limite in forma indeterminata $frac{0}{0}$

$lim_{x rightarrow 4^+} -frac{x^2-7x+12}{8x-x^2-16} =$$lim_{x rightarrow 4^+} -frac{(x-4)cdot (x-3)}{-(x^2-8x+16)} =$$lim_{x rightarrow 4^+} -frac{(x-4)cdot (x-3)}{-(x-4)^2} =$$lim_{x rightarrow 4^+} frac{x-3}{x-4} = +infty$