A cura di: fabio scardia

SVOLGIMENTO:

$v_1= (s_1+s_2)/t= (6,0+3,0)/2 Km/h= 4,5Km/h$

$v_2= (s_1+s_2+s_3)/t=( 6,0+3,0+0)/ 3 Km/h= 3 Km/h$

$v_3= (s_1+s_2+s_3+s_4)/t= (6,0+3,0+0+5,0)/4 Km/h= 3,5Km/h$