A cura di: Alfredo Bochicchio

$[-x^3y^3+(1/2xy)^3-4x^2yxx(1/4xy^2)]:[5xx1/2xyxx(-xy)^2]$
$[-x^3y^3+(1/8x^3y^3)-4x^2yxx(1/4xy^2)]:[5xx1/2xyxx(x^2y^2)]$
$[-x^3y^3+1/8x^3y^3-x^3y^3]:[5/2x^3y^3]$
$[-15/8x^3y^3]:[5/2x^3y^3]$
$-3/4$