A cura di: Administrator

Derivare la funzione

$f(x) = frac{1}{sqrt{2x + 3}} = (2x + 3)^{-1/2}$ $f'(x) = -frac{1}{2}cdot (2x + 3)^{-frac{1}{2} – 1} = -frac{1}{2}cdot (2x + 3)^{-3/2} =$ $-frac{1}{2 sqrt{(2x + 3)^3}}$