A cura di: Administrator

Limite in forma indeterminata $frac{0}{0}$

$lim_{x rightarrow 2} frac{x^2-4}{x^2-3x+2}=$$lim_{x rightarrow 2} frac{(x+2)cdot (x-2)}{(x-1)cdot (x-2)}=$$lim_{x rightarrow 2} frac{x+2}{x-1} = 4$