A cura di: Alfredo Bochicchio
$[(1/4ab^2)^3:(1/8a^2b^2]^2:[(1/2a^4b^3):(2/5a^2b)]$
$[(64a^3b^6):(1/8a^2b^2)]^2:[5/4a^2b^2]$
$[1/8ab^4]^2:[5/4a^2b^2]$
$[1/64a^2b^8]:[5/4a^2b^2]$
$1/80b^6$
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