A cura di: Administrator
Limite in forma indeterminata $frac{infty}{infty}$
$lim_{x rightarrow +infty} frac{x^6-sqrt{x^5+1}} {3+2sqrt{4x^{12}+x^2}} = lim_{x rightarrow +infty} frac{x^6-x^6sqrt{frac{1}{x^7}+frac{1}{x^{12}}}}{3+2x^6sqrt{4+frac{1}{x^{10}}}} =$$lim_{x rightarrow +infty} frac{1-sqrt{frac{1}{x^7}-frac{1}{x^{12}}}}{frac{3}{x^6}+2sqrt{4+frac{1}{x^{10}}}} = frac{1}{4}$
- Matematica
- Matematica - Esercizi sui Limiti